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− | + | =[[MA351]] MA 351 Homework 8= | |
+ | (Copied from [[User_talk:wang403]].) | ||
+ | ---- | ||
+ | ==3.2 #24 == | ||
+ | |||
+ | When a vector [V] is in the span of Ker(A), it means that the linear transformation of [V]([A])=the zero vector. | ||
+ | |||
+ | So... The vector that makes the vector A zero is in the span of Ker(A) | ||
+ | |||
+ | ==3.2 #28 == | ||
+ | |||
+ | Use theorem 3.2.4. | ||
+ | |||
+ | But first determine whether each column is linearly independent. | ||
+ | |||
+ | ==3.2 #45== | ||
+ | |||
+ | Use summary 3.1.8 on Pg. 109 | ||
+ | |||
+ | Note that ker(A)=zero vector, that means all columns in A are linearly independent. | ||
+ | |||
+ | ==3.3 #28 == | ||
+ | |||
+ | to form a basis of R4, the RREF of A must be I4. | ||
+ | ---- | ||
+ | [[2010_Fall_MA_35100_Kummini|Back to MA 351 Prof. Kummini]] | ||
+ | this is me testing out how to use project RHEA |
Revision as of 11:52, 30 November 2010
MA351 MA 351 Homework 8
(Copied from User_talk:wang403.)
3.2 #24
When a vector [V] is in the span of Ker(A), it means that the linear transformation of [V]([A])=the zero vector.
So... The vector that makes the vector A zero is in the span of Ker(A)
3.2 #28
Use theorem 3.2.4.
But first determine whether each column is linearly independent.
3.2 #45
Use summary 3.1.8 on Pg. 109
Note that ker(A)=zero vector, that means all columns in A are linearly independent.
3.3 #28
to form a basis of R4, the RREF of A must be I4.
Back to MA 351 Prof. Kummini this is me testing out how to use project RHEA