Line 4: Line 4:
  
  
This h>is in regards to Homework 3 Problem 4. In order to show that <math>{f}</math> is constant on <math>\Omega</math> I let <math>\gamma</math> be a closed circle in <math>\Omega</math>.  Knowing that <math>{f}</math> is analytic on <math>\Omega</math> we know the integral over <math>\gamma</math> is zero.  Letting <math>\omega\in\gamma</math> we can set <math>f(\omega)=z\in\Gamma</math>.  My question is based on <math>\rho</math> and what we know about it and how it relates to <math>\Gamma</math> what can we know about <math>f(\gamma)</math>?  I think this will help as far as proving f is constant.
+
This is in regards to Homework 3 Problem 4. In order to show that <math>{f}</math> is constant on <math>\Omega</math> I let <math>\gamma</math> be a closed circle in <math>\Omega</math>.  Knowing that <math>{f}</math> is analytic on <math>\Omega</math> we know the integral over <math>\gamma</math> is zero.  Letting <math>\omega\in\gamma</math> we can set <math>f(\omega)=z\in\Gamma</math>.  My question is based on <math>\rho</math> and what we know about it and how it relates to <math>\Gamma</math> what can we know about <math>f(\gamma)</math>?  I think this will help as far as proving f is constant.

Revision as of 10:42, 8 February 2010


Homework 3

This is in regards to Homework 3 Problem 4. In order to show that $ {f} $ is constant on $ \Omega $ I let $ \gamma $ be a closed circle in $ \Omega $. Knowing that $ {f} $ is analytic on $ \Omega $ we know the integral over $ \gamma $ is zero. Letting $ \omega\in\gamma $ we can set $ f(\omega)=z\in\Gamma $. My question is based on $ \rho $ and what we know about it and how it relates to $ \Gamma $ what can we know about $ f(\gamma) $? I think this will help as far as proving f is constant.

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva