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Then, <math>f(E) = {y : 1/4 <= y <= 1}</math>
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Then, <math>f(E) = {y : 1/4 \le y \le 1}</math>

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I am having trouble with question 8 from our first HW. I am going back and trying to fix my old HW. I got back my HW and got a 0 out of 25. Can any one help get me started?

Thanks,

Andrew


8.(a)

$ f(1) = 1 / 1^2 = 1 / 1 = 1 $

$ f(2) = 1 / 2^2 = 1/4 $


Then, $ f(E) = {f(x) : 1 \le x \le 2} $

$ 1/4 \le f(E) \le 1 $


Then, $ f(E) = {y : 1/4 \le y \le 1} $

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