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Andrew
 
Andrew
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8.(a)
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<math>f(1) = 1 / 1^2 = 1 / 1 = 1</math>
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<math>f(2) = 1 / 2^2 = 1/4 </math>
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Then, <math>f(E) = {f(x) : 1 <= x <= 2}</math>
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<math> 1/4 <= f(E) <= 1</math>
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Then, <math>f(E) = {y : 1/4 <= y <= 1}</math>

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I am having trouble with question 8 from our first HW. I am going back and trying to fix my old HW. I got back my HW and got a 0 out of 25. Can any one help get me started?

Thanks,

Andrew


8.(a)

$ f(1) = 1 / 1^2 = 1 / 1 = 1 $ $ f(2) = 1 / 2^2 = 1/4 $

Then, $ f(E) = {f(x) : 1 <= x <= 2} $ $ 1/4 <= f(E) <= 1 $

Then, $ f(E) = {y : 1/4 <= y <= 1} $

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