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'''Problem 18''' (A problem with problem 18). By checking the inequality for <math>n=1</math>  
 
'''Problem 18''' (A problem with problem 18). By checking the inequality for <math>n=1</math>  
one finds that <math>=</math> holds rather then <math> \le  </math>. <br><br> In fact, the  
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one finds that <math>=</math> holds rather then <math> > </math>. <br><br> In fact, the  
inequality holds for <math>n=2</math>. In your assignment, you can either use <math>\leq</math> or prove that the <math>\le </math> holds for <math>n\ge 2</math>.
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inequality holds for <math>n=2</math>. In your assignment, you can either use <math>\ge</math> or prove that the <math> > </math> holds for <math>n\ge 2</math>.
  
  
 
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Revision as of 14:18, 18 January 2010

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Problem 18 (A problem with problem 18). By checking the inequality for $ n=1 $ one finds that $ = $ holds rather then $ > $.

In fact, the inequality holds for $ n=2 $. In your assignment, you can either use $ \ge $ or prove that the $ > $ holds for $ n\ge 2 $.



Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood