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so how many squares and cubics: (1,000)^1/6 = 3 | so how many squares and cubics: (1,000)^1/6 = 3 | ||
| + | |||
| + | ---- | ||
| + | |||
| + | 12. | ||
| + | A: # of squares: 31 | ||
| + | B: # of cubics: 10 | ||
| + | A intersection B: 3 | ||
| + | |||
| + | 31+10-3=38 | ||
Revision as of 14:11, 3 September 2008
Concerning #28 in 7.5
Can someone rephrase the question or shed some light on what this question is asking? I looked at the solution for #29 which seems to be quite similar, but it was a notation we haven't learned in class.
Also it would be amazing if someone could explain the intersection between A and B on problem number 12. I have so far the squares being 31 and the cubes being 10. But I am not sure how to get the intersection. Any ideas? Also I do not understand 20 or 28 at all. If someone could please help me out that would ROCK! Thanks
I think that if you want numbers between 1 and 1,000 that are both cubes and squares you'd do (1,000)^1/6 but thats just my guess because when you want,
how many squares: (1,000)^1/2 = 31
how many cubics: (1,000)^1/3= 10
so how many squares and cubics: (1,000)^1/6 = 3
12. A: # of squares: 31 B: # of cubics: 10 A intersection B: 3
31+10-3=38
