Difference between revisions of "HW 4" - Rhea

Revision as of 09:26, 22 September 2009

• For problem number one, I see that the sum of the areas of the four small triangles is equal to the area of quadrilateral MNPQ. Is this the result we're looking for? It seems a little too obvious but I can't figure anything else out.

I also stated for number one that the area of the little paralllogram is half that of the big parallelogram and that the area of all of the little triangles i equal to the area of the little parallelogram

I am really bad with sketchpad and having trouble with number 2. Can anyone help me get started? -chris [sure. at what point are you getting hung up on? - sue]

• thanks anyways i got it. For any one need help with it, just calculate the lengths and think of thm 28 (multiply)

any hints for # 10 - sue

for # 3, if anyone has gotten it, is it a bunch of summing of areas?

it is!

for #3, what areas might we be summing? I remember with the example, the intersection was inside the triangle, so we could use the area of the triangle... any hints? ~Lauren

with p being ouside, there are now 2 little triangles outside the bigger eq triangle. sum all of the triangles in one direction than all of them in another direction - if that makes sense. what I did was write down the areas for all of the triangles ad see which ones give me what I neede - Sue

I'm down to 9 and 10 now. no clue on 9 - Sue