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== Convergence of Z Transform == | == Convergence of Z Transform == | ||
| − | '''Definition:''' A series <math>\sum_{\infty}^{n=0} a_n</math> is said to converge to a value V if for every <math>\epsilon > 0</math>, there exists a positive integer M such that <math>|\sum_{n=0}^{N-1} a_n - V | < \epsilon, for all N > M | + | '''Definition:''' A series <math>\sum_{\infty}^{n=0} a_n</math> is said to converge to a value V if for every <math>\epsilon > 0</math>, there exists a positive integer M such that <math>|\sum_{n=0}^{N-1} a_n - V | < \epsilon,</math> for all N > M |
For the Z transform, it is customary to talk about the "region of absolute convergence." | For the Z transform, it is customary to talk about the "region of absolute convergence." | ||
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'''Fact 3:''' If x[n] is anti-causal (i.e. x[n] = 0 for n > 0) and <math>z_0</math> is included in ROC, then any z with <math>|z|< z_0</math> is also in ROC. Has a similar proof. | '''Fact 3:''' If x[n] is anti-causal (i.e. x[n] = 0 for n > 0) and <math>z_0</math> is included in ROC, then any z with <math>|z|< z_0</math> is also in ROC. Has a similar proof. | ||
| − | '''Fact 4:''' If x[n] is "mixed causal" (two-sided signal) and <math>z_0</math> is included in ROC then there exist <math>r_1, r_2 included in all real numbers \ge 0, r_1 <|z|< r_2</math> such that X(z) converges for all z with <math>r_1 <|z|< r_2</math>. | + | '''Fact 4:''' If x[n] is "mixed causal" (two-sided signal) and <math>z_0</math> is included in ROC then there exist <math>r_1, r_2</math> included in all real numbers <math>\ge 0, r_1 <|z|< r_2</math> such that X(z) converges for all z with <math>r_1 <|z|< r_2</math>. |
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| + | The complex plan contains an important point z = <math>\infty</math>, which cannot be compressed into the sphere. | ||
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| + | '''Definition:''' We say that X(z) converges at z = <math>\infty</math> if <math>X(\frac{1}{z})</math> converges at 0 | ||
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| + | Example 1: | ||
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| + | <math>x_1[n] = \delta [n-1]</math> | ||
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| + | <math>X_1(z) = \sum^{\infty}_{n=- \infty} \delta [n-1]z^{-n} = \frac{1}{z}</math>, which is well-defined everywhere except z = 0 | ||
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| + | Now <math>X_1(\frac{1}{z}) = z</math> is well-defined at z = 0 <math>\rightarrow z= \infty</math> is in ROC | ||
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| + | ROC: all of the complex plane except z = 0 | ||
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| + | Example 2: | ||
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| + | <math>x_2[n] = \delta [n+1]</math> | ||
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| + | <math>X_2(z) = \sum^{\infty}_{n=- \infty} \delta [n+1]z^{-n} =z</math>, which is well-defined everywhere on the finite complex plane | ||
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| + | Now <math>X_2(\frac{1}{z}) = \frac{1}{z}</math> is infinite at z = 0 <math>\rightarrow z= \infty</math> is not in ROC | ||
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| + | ROC: finite complex plane | ||
Revision as of 17:55, 21 September 2009
Convergence of Z Transform
Definition: A series $ \sum_{\infty}^{n=0} a_n $ is said to converge to a value V if for every $ \epsilon > 0 $, there exists a positive integer M such that $ |\sum_{n=0}^{N-1} a_n - V | < \epsilon, $ for all N > M
For the Z transform, it is customary to talk about the "region of absolute convergence."
Definition: A series $ \sum^{\infty}_{n=0} a_n $ is called "absolutely convergent" when $ \sum_{n=0}^{\infty} |a_n | $ converges.
Fact: If $ \sum|a_n| $ converges, then $ \sum a_n $ converges also, i.e. the region of absolute convergence is included in the region of convergence.
In the literature and here: ROC means "region of absolute convergence"
Reference for Z transform: Chapter 10 of the ECE 301 book
Facts about ROC
X(z) converges absolutely
$ \leftrightarrow \sum_n |x[n]z^{-n}| $ converges
$ \leftrightarrow \sum_n |x[n]||z^{-n}| $ converges
Fact 1: ROC is made of rings around the origin. If $ z_0 $ is in the ROC, then any other z with $ |z| = |z_0| $ is also in the ROC
Fact 2: If x[n] is "causal" (i.e. x[n] = 0 for all n < 0) and $ z_0 $ is in the ROC then any z with $ |z|>|z_0| $ is also in the ROC
Proof for z with $ |z|> |z_0| $: $ \sum_{n=- \infty}^{\infty}|x[n]z^{-n}| = \sum_{n=0}^{\infty}|x[n]z^{-n}| = \sum_{n=0}^{\infty}|x[n]|{|z|}^{-n} $
$ \le \sum_{n=0}^{\infty}|x[n]|{|z_0|}^{-n} = \sum_{n=0}^{\infty}|x[n]z_0^{-n}| $ which converges by assumption
$ \rightarrow $ X(z) converges absolutely
Fact 3: If x[n] is anti-causal (i.e. x[n] = 0 for n > 0) and $ z_0 $ is included in ROC, then any z with $ |z|< z_0 $ is also in ROC. Has a similar proof.
Fact 4: If x[n] is "mixed causal" (two-sided signal) and $ z_0 $ is included in ROC then there exist $ r_1, r_2 $ included in all real numbers $ \ge 0, r_1 <|z|< r_2 $ such that X(z) converges for all z with $ r_1 <|z|< r_2 $.
The complex plan contains an important point z = $ \infty $, which cannot be compressed into the sphere.
Definition: We say that X(z) converges at z = $ \infty $ if $ X(\frac{1}{z}) $ converges at 0
Example 1:
$ x_1[n] = \delta [n-1] $
$ X_1(z) = \sum^{\infty}_{n=- \infty} \delta [n-1]z^{-n} = \frac{1}{z} $, which is well-defined everywhere except z = 0
Now $ X_1(\frac{1}{z}) = z $ is well-defined at z = 0 $ \rightarrow z= \infty $ is in ROC
ROC: all of the complex plane except z = 0
Example 2:
$ x_2[n] = \delta [n+1] $
$ X_2(z) = \sum^{\infty}_{n=- \infty} \delta [n+1]z^{-n} =z $, which is well-defined everywhere on the finite complex plane
Now $ X_2(\frac{1}{z}) = \frac{1}{z} $ is infinite at z = 0 $ \rightarrow z= \infty $ is not in ROC
ROC: finite complex plane
