Revision as of 10:01, 16 September 2009

HW 3

Does anyone have any hints for #2. I can't seem to figure it out, I may be misunderstanding some of the directions. -Mary

Do you mean number 2 the geometer's sketchpad? Or do you mean number two as in the proof section?? -Brittany

I know a lot of people have been having trouble with this problem. I know someone was going to email Uli last night. I would just continually check on here for help. - Dana

I'm not sure if you are having trouble drawing the figure or figuring out the equation. So I'll try to cover both, for drawing the figure start with two points and then make a segment between them. Then choose one of the points and the segment and ask for a circle with radius. Do the same thing again only using the other point, then the third point is the intersection of the circles. As far as the formula is concerned, use addition and subtraction. Hope this is helpful.--Shore 14:20, 16 September 2009 (UTC)

Does anyone have something for problem 6. I'm having trouble with it for some reason. -Jon

Hey Jon, number 6 is exactly like the proof in the book for case one...the congruent triangles are simply on the outside of triangle(ABC). Just connect AX,BX,PX,and CX and look at congruent triangles formed! --Jrhaynie 15:01, 16 September 2009 (UTC)

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