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<math>\sum_{n = M}^N \alpha^n</math>
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<math>\sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1}</math>

Revision as of 01:41, 20 July 2009

$ \sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1} $

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010