(New page: Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scram...) |
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Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scrambled. I think I'm gonna try to rewrite the sum and see what that gets me. | Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scrambled. I think I'm gonna try to rewrite the sum and see what that gets me. | ||
| − | <math>\frac{n!}{n^n}=\frac{(n-1)!}{n^{n-1}}<math> | + | <math>\frac{n!}{n^n}=\frac{(n-1)!}{n^{n-1}}</math> |
| − | Don't know what that will do, but we'll see. | + | Don't know what that will do, but we'll see. [[User:Jhunsber|His Awesomeness, Josh Hunsberger]] |
Revision as of 18:50, 4 November 2008
Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scrambled. I think I'm gonna try to rewrite the sum and see what that gets me.
$ \frac{n!}{n^n}=\frac{(n-1)!}{n^{n-1}} $
Don't know what that will do, but we'll see. His Awesomeness, Josh Hunsberger
