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<math>a_n < \frac{1}{n}</math> | <math>a_n < \frac{1}{n}</math> | ||
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| + | [[User:Idryg|Idryg]] 14:51, 28 October 2008 (UTC) | ||
Revision as of 09:51, 28 October 2008
Okay, so the problem is:
$ a_n = \frac{n!}{n^n} $
And, it hints to compare this with $ \frac{1}{n} $.
I don't get really how to compare these two.. I mean, I can see that the denominator of $ a_n $ will grow much faster than the numerator.
I'm guessing the limit approaches 0 as n approaches infinity, but I'm not sure how to mathematically show that
$ a_n < \frac{1}{n} $
Idryg 14:51, 28 October 2008 (UTC)
