Difference between revisions of "Page 563: Problem 11 MA181Fall2008bell" - Rhea
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Revision as of 12:03, 13 October 2008
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Latest revision as of 12:06, 13 October 2008
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* I didn't get the right answer according to the back of the book. I got:
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<math>x + 4 = Ax + A + Bx - 6B = (A + B)x + A - 6B</math>
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Meaning:
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<math>A + B = 1</math>
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and
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<math>A - 6B = 4</math>
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So, <math>A = \frac{10}{7}</math> and <math>B = -\frac{3}{7}</math>
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The answer in the back of the book is
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<math>\frac{1}{7}\ln{|(x+6)^2(x-1)^5|}+C</math>
Latest revision as of 12:06, 13 October 2008
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