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'''p*Ei(x(log(r)-log(p)))''' | '''p*Ei(x(log(r)-log(p)))''' | ||
| − | Note: <math> Ei(x) = \int_{ | + | Note: <math> Ei(x) = \int_{x}^{\infty} \frac{e^{-t}}{t} dt </math> |
I don't know how to use this integral, but I did some manipulation and got this: | I don't know how to use this integral, but I did some manipulation and got this: | ||
Revision as of 09:55, 2 October 2008
First off, this is not part of homework. This equation (if I did it right) is the summation of an investment 'A' that gains interest over period 'p' and time 't' in years. The investment 'A' is added every period. I originally got $ A \sum_{t=0}^{n} \frac{r^t}{p^{t}} dt $, but I wanted to turn it into an integral and pulled out a $ \frac{t}{p} $ so I would have a dt. That led me to the integral below. Does it make sense and does anyone know how to integrate the problem?
Integrate this:
$ A \int_{0}^{n} \frac{r^t}{t*p^{t-1}} dt $
I searched how to do it on matlab, but could not find it. Then, I found this website on Wolfram. It integrates it using mathematica. Here is what it got:
p*Ei(x(log(r)-log(p)))
Note: $ Ei(x) = \int_{x}^{\infty} \frac{e^{-t}}{t} dt $
I don't know how to use this integral, but I did some manipulation and got this:
$ Total = \frac{A[(r+1)^{t+1}-(r+1)]}{r} $
