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v= int(a,b) of(2pi*x*(f(x)-g(x))) | v= int(a,b) of(2pi*x*(f(x)-g(x))) | ||
xbar= int(a,b) of(x*(f(x)-g(x)))/A | xbar= int(a,b) of(x*(f(x)-g(x)))/A | ||
+ | 5) | ||
+ | a) | ||
+ | b) | ||
+ | c) | ||
+ | d) |
Revision as of 08:06, 25 September 2008
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Math 181 Honors Calculus
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tests solution
1)
a) b)
2)a) f(x) = int(o,sqrtx)of e^t^2 dt
chain rule where u = squrt x using funamental therem of calc f(u)= int(0,u) of e^t^2 dt = e^u^2(1/2*x^(-1/2)) = (e^x)/(2sqrt(x)) lim of x as x goes to inf x/f(x)= lim of x as x goes to inf 1/f'(x)= lim of x as x goes to inf 1/(e^x/(2sqrt(x))= lim of x as x goes to inf (2sqrt(x))/(e^x)= lim of x as x goes to inf 1/(sqrt(x)e^x)= 0
3)
4)
v= 2pi*xbar*A v= int(a,b) of(2pi*x*(f(x)-g(x))) xbar= int(a,b) of(x*(f(x)-g(x)))/A
5)
a) b) c) d)