Line 2: Line 2:
  
 
Sample Case: One flip of coin
 
Sample Case: One flip of coin
 +
 
P(H)=0.5
 
P(H)=0.5
 
P(T)=0.5
 
P(T)=0.5
P(H<math>union</math>T)=0 (You can't have both H and T in one flip)
+
P(H∩T)=0 (You can't have both H and T in one flip)
  
 
(0.5)*(0.5)≠0
 
(0.5)*(0.5)≠0
Not independent
+
  Not independent

Revision as of 19:06, 4 March 2009

If Independent then P(H)*P(T)=P(H∩T)

Sample Case: One flip of coin

P(H)=0.5 P(T)=0.5 P(H∩T)=0 (You can't have both H and T in one flip)

(0.5)*(0.5)≠0

 Not independent

Alumni Liaison

has a message for current ECE438 students.

Sean Hu, ECE PhD 2009