(New page: If Independent then P(H)*P(T)=P(H<math>union</math>T) Sample Case: One flip of coin P(H)=0.5 P(T)=0.5 P(H<math>union</math>T)=0 (You can't have both H and T in one flip) (0.5)*(0.5)=0 No...) |
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− | If Independent then P(H)*P(T)=P( | + | If Independent then P(H)*P(T)=P(H∩T) |
Sample Case: One flip of coin | Sample Case: One flip of coin | ||
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P(H<math>union</math>T)=0 (You can't have both H and T in one flip) | P(H<math>union</math>T)=0 (You can't have both H and T in one flip) | ||
− | (0.5)*(0.5) | + | (0.5)*(0.5)≠0 |
Not independent | Not independent |
Revision as of 19:05, 4 March 2009
If Independent then P(H)*P(T)=P(H∩T)
Sample Case: One flip of coin P(H)=0.5 P(T)=0.5 P(H$ union $T)=0 (You can't have both H and T in one flip)
(0.5)*(0.5)≠0 Not independent