(New page: If Independent then P(H)*P(T)=P(H<math>union</math>T) Sample Case: One flip of coin P(H)=0.5 P(T)=0.5 P(H<math>union</math>T)=0 (You can't have both H and T in one flip) (0.5)*(0.5)=0 No...)
 
Line 1: Line 1:
If Independent then P(H)*P(T)=P(H<math>union</math>T)
+
If Independent then P(H)*P(T)=P(H∩T)
  
 
Sample Case: One flip of coin
 
Sample Case: One flip of coin
Line 6: Line 6:
 
P(H<math>union</math>T)=0 (You can't have both H and T in one flip)
 
P(H<math>union</math>T)=0 (You can't have both H and T in one flip)
  
(0.5)*(0.5)=0
+
(0.5)*(0.5)≠0
 
Not independent
 
Not independent

Revision as of 19:05, 4 March 2009

If Independent then P(H)*P(T)=P(H∩T)

Sample Case: One flip of coin P(H)=0.5 P(T)=0.5 P(H$ union $T)=0 (You can't have both H and T in one flip)

(0.5)*(0.5)≠0 Not independent

Alumni Liaison

ECE462 Survivor

Seraj Dosenbach