Difference between revisions of "Chapter 3: Problem 48" - Rhea

Latest revision as of 19:00, 5 February 2009

For this problem, does anyone know what the new conjecture is supposed to be? I thought it might just be that the order of r multiplied by the order of s is NOT the order of rs, but I wasn't sure if there was another conjecture that could be made. --Clwarner 21:14, 3 February 2009 (UTC)

The conjecture I made was that $ \scriptstyle gcd(r,s)=1\ \leftrightarrow\ \mid U(r)\mid*\mid U(s)\mid=\mid U(rs)\mid $.

--Nick Rupley 05:01, 4 February 2009 (UTC)

I made an equivalent conjecture: If r and s are relatively prime, then U(r) * U(s) = U(r*s).

--Yu Suo

I discovered the same conjectur: U(r) * U(s) = U(r*s)

--John Zage

Obviously the conjecture they are leading you to is that U(r)*U(s)=U(r*s) but only if gcd(r*s)=1

--Dane DeSutter