(New page: This problem is quiet similar with the lecture example, except for the [-a,a] instead of [0,a]) |
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This problem is quiet similar with the lecture example, except for the [-a,a] instead of [0,a] | This problem is quiet similar with the lecture example, except for the [-a,a] instead of [0,a] | ||
+ | fxi(xi;a)=1/(2a) if -a=<xi=<a, i.e |xi|<=a; and =0 if |xi|>a | ||
+ | therefore, if any |xi|>a, the whole thing is zero | ||
+ | for a>=max|xi| | ||
+ | fx1..xn(x1..xn;a)=(1/2a)^n, is an decreasing function | ||
+ | |||
+ | when a=max|xi|, function is max. |
Latest revision as of 11:32, 10 November 2008
This problem is quiet similar with the lecture example, except for the [-a,a] instead of [0,a] fxi(xi;a)=1/(2a) if -a=<xi=<a, i.e |xi|<=a; and =0 if |xi|>a therefore, if any |xi|>a, the whole thing is zero for a>=max|xi| fx1..xn(x1..xn;a)=(1/2a)^n, is an decreasing function
when a=max|xi|, function is max.