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| − | One theorem that could be a good candidate for my favorite one is is mm.. there are many funny names to it: the theorem about two policemen(militsioner), the sandwich theorem, squeeze theorem.. So the definition. We have 3 functions f, g, h on some certain interval, and they hold following inequality on this interval: <math>g(x)\le f(x) \le h(x)</math>. So if there is some point 'a' in that interval that <math>\lim_{x \to a}g(x) = L </math> and <math>\lim_{x \to a}h(x) = L </math> THEN <math>\lim_{x \to a}f(x) = L </math> too. | + | One theorem that could be a good candidate for my favorite one is is mm.. there are many funny names to it: the theorem about two policemen(militsioner), the sandwich theorem, squeeze theorem.. So the definition. We have 3 functions f, g, h on some certain interval, and they hold following inequality on this interval: <math>g(x)\le f(x) \le h(x)</math>. So if there is some point 'a' in that interval that <math>\lim_{x \to a}g(x) = L </math> and <math>\lim_{x \to a}h(x) = L </math> THEN <math>\lim_{x \to a}f(x) = L </math> too. So basically, g and h "squeeze" the f function into that L limit. Funny name and intuitively easy to understand theorem, but important one in solving and proving other theorems and problems. |
Revision as of 12:14, 25 January 2009
One theorem that could be a good candidate for my favorite one is is mm.. there are many funny names to it: the theorem about two policemen(militsioner), the sandwich theorem, squeeze theorem.. So the definition. We have 3 functions f, g, h on some certain interval, and they hold following inequality on this interval: $ g(x)\le f(x) \le h(x) $. So if there is some point 'a' in that interval that $ \lim_{x \to a}g(x) = L $ and $ \lim_{x \to a}h(x) = L $ THEN $ \lim_{x \to a}f(x) = L $ too. So basically, g and h "squeeze" the f function into that L limit. Funny name and intuitively easy to understand theorem, but important one in solving and proving other theorems and problems.
