m |
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Line 2: | Line 2: | ||
<math>\sqrt(A) cos(2pi*drand48())</math> | <math>\sqrt(A) cos(2pi*drand48())</math> | ||
+ | |||
+ | where A is still the exponential RV calculated in 1b. |
Revision as of 10:31, 21 October 2008
Regarding Seraj's solution, i believe the solution would be
$ \sqrt(A) cos(2pi*drand48()) $
where A is still the exponential RV calculated in 1b.