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I got the same as Ozgur, and I verified it by multiplying and adding the remainder.  --[[User:Dakinsey|Dakinsey]] 11:27, 5 November 2008 (UTC)
 
I got the same as Ozgur, and I verified it by multiplying and adding the remainder.  --[[User:Dakinsey|Dakinsey]] 11:27, 5 November 2008 (UTC)
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I also got a quotient of 4x^2+3x+6 and a remainder of 6x+2.....

Latest revision as of 04:14, 6 November 2008

Use long division like in Example 1 except the coefficients belong to $ Z_7 $. My final answer was $ q=4x^2+3x+6 $ and $ r=6x $. Can anyone confirm?


I have the same thing for the quotient, but I have 6x+2 for the remainder.

-Ozgur

To verify my solution to f/g, where f, g are the given polynomials, I just checked that f = qg + r, where q is my quotient, and r is my remainder. This is how you can be sure.

I got the same as Ozgur, and I verified it by multiplying and adding the remainder. --Dakinsey 11:27, 5 November 2008 (UTC)


I also got a quotient of 4x^2+3x+6 and a remainder of 6x+2.....

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