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I don't understand how the P[U<=F(x)] = F(x)can someone explain this? | I don't understand how the P[U<=F(x)] = F(x)can someone explain this? | ||
| + | |||
| + | //Comment | ||
| + | This can be said because it was given to us that the function is a "non-decreasing function" and that U is a uniform random variable. This is enough information to make this step. So, | ||
| + | :<math> | ||
| + | \begin{align} | ||
| + | & {} \Pr(U \leq F(x)) = F(x)\quad \text{(because }\Pr(U \leq y) = y,\text{ since }U\text{ is uniform on the unit interval)} | ||
| + | \end{align} | ||
| + | </math> | ||
Revision as of 04:31, 21 October 2008
I don't understand how the P[U<=F(x)] = F(x)can someone explain this?
//Comment
This can be said because it was given to us that the function is a "non-decreasing function" and that U is a uniform random variable. This is enough information to make this step. So,
- $ \begin{align} & {} \Pr(U \leq F(x)) = F(x)\quad \text{(because }\Pr(U \leq y) = y,\text{ since }U\text{ is uniform on the unit interval)} \end{align} $
