(New page: <math>x[n]=sin[\omega n]u[n]</math>) |
|||
| Line 1: | Line 1: | ||
| − | <math> | + | <math>sin[\omega _0 n]u[n]\rightarrow \frac{1}{2j}[\frac{1}{1-e^{-j(\omega -\omega _0)}}-\frac{1}{1-e^{-j(\omega +\omega _0)}}]</math> |
Latest revision as of 17:11, 15 October 2008
$ sin[\omega _0 n]u[n]\rightarrow \frac{1}{2j}[\frac{1}{1-e^{-j(\omega -\omega _0)}}-\frac{1}{1-e^{-j(\omega +\omega _0)}}] $
