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<math>x(t)= sin(2{\Pi}t+ {\Pi}/4)</math>
 
<math>x(t)= sin(2{\Pi}t+ {\Pi}/4)</math>
  
<math>x(t)= e^(2{\Pi}t+ {\Pi}/4)j-e^-(2{\Pi}t+ {\Pi}/4)j</math>
+
<math>x(t)= \frac{e^2{\Pi}t+ {\Pi}j/4-e^-2{\Pi}t+ {\Pi}j/4}{2j}</math>

Revision as of 22:30, 6 October 2008

$ x(t)= sin(2{\Pi}t+ {\Pi}/4) $

$ x(t)= \frac{e^2{\Pi}t+ {\Pi}j/4-e^-2{\Pi}t+ {\Pi}j/4}{2j} $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood