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<math>x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}X(\omega)e^{-j\omega t}d\omega</math> | <math>x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}X(\omega)e^{-j\omega t}d\omega</math> | ||
− | <math>X(\omega | + | <math>X(\omega) = \delta(\omega - 4\pi)</math> |
Revision as of 09:18, 3 October 2008
Inverse Fourier Transform
$ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}X(\omega)e^{-j\omega t}d\omega $
$ X(\omega) = \delta(\omega - 4\pi) $