(Part A)
Line 9: Line 9:
  
 
<math>= K e^{-jwa}e^{jwt}</math>
 
<math>= K e^{-jwa}e^{jwt}</math>
 
==
 
<math>y(t) = K x(t-a)</math>
 
 
if <math>x(t)=e^{jwt} </math> was inputed to the system
 
 
<math>y(t) = K e^{jw(t-a)}</math>
 
 
<math>= K e^{-jwa}e^{jwt}</math> ==
 

Revision as of 17:21, 26 September 2008

Part A

$ y(t) = K x(t-a) $

if $ x(t)=e^{jwt} $ was inputed to the system

$ y(t) = K e^{jw(t-a)} $

$ = K e^{-jwa}e^{jwt} $

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