Line 18: Line 18:
 
</math>
 
</math>
  
where
 
 
<math>
 
<math>
 
\omega_0 = \frac{2\pi}{T} = 1
 
\omega_0 = \frac{2\pi}{T} = 1
 
</math>
 
</math>

Revision as of 12:37, 26 September 2008

The function y(t) in this example is the periodic continuous-time signal cos(t) such that

$ y(t) = \ cos(t) $

where cos(t) can be expressed by the Maclaurin series expansion

$ \ cos(t) = \sum_{n=0}^\infty \left (-1 \right )^n \frac{t^{2n}}{ \left(2n \right )!} $

and its Fourier series coefficients are described by the equation

$ \ a_k = \frac{1}{T}\int_{T}^{\infty} y(t)e^{-jk\omega_0t}\, dt $

$ \omega_0 = \frac{2\pi}{T} = 1 $

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