(→CT Fourier Series) |
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If input is <math>(1 + j)cos(\frac{\pi}{2}t + \pi)sin(\frac{\pi}{4}t)</math> | If input is <math>(1 + j)cos(\frac{\pi}{2}t + \pi)sin(\frac{\pi}{4}t)</math> | ||
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+ | <math>= (1 + j)(\frac {e^{j \frac{\pi}{2}t + \pi j} + e^{-j \frac{\pi}{2}t - \pi j}}{2})(\frac{e^{j \frac{\pi}{4}t} - e^{-j \frac{\pi}{4}t}}{2j})</math> |
Revision as of 08:48, 26 September 2008
CT Fourier Series
If input is $ (1 + j)cos(\frac{\pi}{2}t + \pi)sin(\frac{\pi}{4}t) $
$ = (1 + j)(\frac {e^{j \frac{\pi}{2}t + \pi j} + e^{-j \frac{\pi}{2}t - \pi j}}{2})(\frac{e^{j \frac{\pi}{4}t} - e^{-j \frac{\pi}{4}t}}{2j}) $