| Line 5: | Line 5: | ||
plugging in delta(t) into the system we get: | plugging in delta(t) into the system we get: | ||
| − | + | h(t) = 10delta(t-1) | |
| + | |||
| + | H(s) = \int_{-\infty}^{\infty} h(t) | ||
| + | |||
| + | H(s) = \int_{-\infty}^{\infty} 10delta(t-1) | ||
Revision as of 10:59, 25 September 2008
CT LTI system:
y(t) = 10x(t-1)
plugging in delta(t) into the system we get:
h(t) = 10delta(t-1)
H(s) = \int_{-\infty}^{\infty} h(t)
H(s) = \int_{-\infty}^{\infty} 10delta(t-1)
