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(i did this. sort of.) |
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Homework 4 Ben Horst: [[HW4.1 Ben Horst _ECE301Fall2008mboutin| 4.1]] :: [[HW4.3 Ben Horst _ECE301Fall2008mboutin| 4.3]] :: [[HW4.5 Ben Horst _ECE301Fall2008mboutin| 4.5]] | Homework 4 Ben Horst: [[HW4.1 Ben Horst _ECE301Fall2008mboutin| 4.1]] :: [[HW4.3 Ben Horst _ECE301Fall2008mboutin| 4.3]] :: [[HW4.5 Ben Horst _ECE301Fall2008mboutin| 4.5]] | ||
---- | ---- | ||
+ | ==Problem== | ||
+ | 1. The signal has only two Fourier coefficients (all the rest are 0) | ||
+ | 2. The fundamental period of the signal is 8 | ||
+ | 3. Hint: <math>{1 \over 2}\sin({pi \over 4}t)</math> | ||
+ | |||
+ | ==Solution== | ||
+ | The answer is <math>{1 \over 2}\sin({pi \over 4}t)</math> Surprise! |
Revision as of 16:48, 25 September 2008
Homework 4 Ben Horst: 4.1 :: 4.3 :: 4.5
Problem
1. The signal has only two Fourier coefficients (all the rest are 0) 2. The fundamental period of the signal is 8 3. Hint: $ {1 \over 2}\sin({pi \over 4}t) $
Solution
The answer is $ {1 \over 2}\sin({pi \over 4}t) $ Surprise!