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3. <math>\sum_{n=2}^{9}(-1)^{\frac{3}{4}}x[n]=4</math>. | 3. <math>\sum_{n=2}^{9}(-1)^{\frac{3}{4}}x[n]=4</math>. | ||
| − | 4. <math>a_3=a_5</math>. | + | 4. <math>a_3=a_5</math>. All <math>a_k=0</math> for <math> k\neq{3,5}</math>. |
==So What Is x[n]?== | ==So What Is x[n]?== | ||
Revision as of 07:25, 25 September 2008
Guess the Signal
1. $ x[n] $ is periodic with N=8.
2. $ a_0=0 $.
3. $ \sum_{n=2}^{9}(-1)^{\frac{3}{4}}x[n]=4 $.
4. $ a_3=a_5 $. All $ a_k=0 $ for $ k\neq{3,5} $.
