(→Define a periodic DT signal and compute its Fourier series coefficients.) |
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Line 2: | Line 2: | ||
For DT, | For DT, | ||
− | <math>x | + | <math>x[n]=\sum_{k=0}^{N-1} a_k e^{jk\frac{2\pi}{N} n}</math> |
where | where | ||
− | <math>a_k=\frac{1}{ | + | <math>a_k=\frac{1}{N}\sum_{n=0}^{N-1} x[n] e^{-jk\frac{2\pi}{N} n} </math>. |
Let the signal be | Let the signal be |
Revision as of 09:17, 25 September 2008
Define a periodic DT signal and compute its Fourier series coefficients.
For DT,
$ x[n]=\sum_{k=0}^{N-1} a_k e^{jk\frac{2\pi}{N} n} $
where
$ a_k=\frac{1}{N}\sum_{n=0}^{N-1} x[n] e^{-jk\frac{2\pi}{N} n} $.
Let the signal be