Processing math: 25%
(CT SIGNAL & ITS FOURIER COEFFICIENTS)
(CT SIGNAL & ITS FOURIER COEFFICIENTS)
Line 7: Line 7:
 
=    <math>\frac{e^{jt}-e^{-jt}}{2i}</math>+<math>2*\frac{e^{2jt}+{e^{-2jt}}}{2}</math>
 
=    <math>\frac{e^{jt}-e^{-jt}}{2i}</math>+<math>2*\frac{e^{2jt}+{e^{-2jt}}}{2}</math>
  
=    <math>\frac{-j{e^{jt}}}{2}</math>
+
=    <math>\frac{-j{e^{jt}}}{2}+\frac{j{e^{-jt}}}{2}+{e^{2jt}}+{e^{-2jt}}</math>

Revision as of 13:54, 23 September 2008

CT SIGNAL & ITS FOURIER COEFFICIENTS

Let the input signal be

$ x(t)=sint +2cos2t $

= $ \frac{e^{jt}-e^{-jt}}{2i} $+$ 2*\frac{e^{2jt}+{e^{-2jt}}}{2} $

= $ \frac{-j{e^{jt}}}{2}+\frac{j{e^{-jt}}}{2}+{e^{2jt}}+{e^{-2jt}} $

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