| Line 5: | Line 5: | ||
and the system is linear | and the system is linear | ||
| − | since Euler's formulat states that : <math>e^{ | + | since Euler's formulat states that : <math>e^{jx} = \cos x + j\sin x \!</math> |
| + | |||
| + | <math>e^{2jt} = \cos 2t + j\sin 2t \!</math> | ||
| + | |||
| + | and | ||
| + | |||
| + | <math>e^{-2jt} = \cos -2t + j\sin -2t \!</math> | ||
| + | <math> = \cos -2t + j\sin -2t \!</math> | ||
Revision as of 14:52, 19 September 2008
$ e^{2jt} $ yields $ te^{-2jt} $ and $ e^{-2jt} $ yields $ te^{2jt} $
and the system is linear
since Euler's formulat states that : $ e^{jx} = \cos x + j\sin x \! $
$ e^{2jt} = \cos 2t + j\sin 2t \! $
and
$ e^{-2jt} = \cos -2t + j\sin -2t \! $ $ = \cos -2t + j\sin -2t \! $
