(Linearity)
(Linearity)
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Based on the given information, we know that the system must be linear.  Since it is linear (and has the output shown in paragraph 1), we can conclude that it must have the output:
+
Based on the given information, we know that the system must be linear.  Since it is linear (and has the output shown above in line 1), we can conclude that it must have the output:
  
 
<math> \frac{1}{2}(te^{-2jt}+te^{2jt})\!</math>.   
 
<math> \frac{1}{2}(te^{-2jt}+te^{2jt})\!</math>.   

Revision as of 15:16, 18 September 2008

Linearity

If a linear system has a response to $ e^{2jt}\! $ of $ t*e^{-2jt}\! $ and a response to $ e^{-2jt}\! $ of $ t*e^{2jt}\! $, then it's response to $ cos(2t)\! $ must be $ t*cos(2t)\! $

To look at this in more detail, we must first understand that $ cos(2t)\! $ can be expressed as follows: $ \frac{1}{2}(e^{-2jt}+e^{2jt})\! $


Based on the given information, we know that the system must be linear. Since it is linear (and has the output shown above in line 1), we can conclude that it must have the output:

$ \frac{1}{2}(te^{-2jt}+te^{2jt})\! $.

Upon converting the output (above) back into a cosine function, we get the output:

$ t*cos(2t)\! $

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva