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we determine:
 
we determine:
 
<math> x[n] = cos(\pi*n) = \frac{e^{j*\pi*n} + e^{-j*\pi*n}}{2} </math>
 
<math> x[n] = cos(\pi*n) = \frac{e^{j*\pi*n} + e^{-j*\pi*n}}{2} </math>
 +
  
  
 
yields to <math> x[t*n] = \frac{te^{j*\pi*n} + t*e^{-j*\pi*n}}{2} </math>
 
yields to <math> x[t*n] = \frac{te^{j*\pi*n} + t*e^{-j*\pi*n}}{2} </math>
 +
 +
<math> == cos(\pi*n) -> -1 </math> on every even integer interval.

Revision as of 15:35, 18 September 2008

The Basics of Linearity

A system is linear if its inputs are sequentially equal to the outputs for a certain function:

$ x(t) = a*x1(t) + b*x2(t) = a*y1(t) + b*y2(t) $


Take for a simple example:

Ex) What is the output of:

$ x[n] = e^{j*\pi*n} -> n*e^{-j*\pi*n} $

$ x[n] \to Sys 1 \to n*x[-n] $


from: $ e^{j*n*y} = cos(n*y) + j*sin(n*y) $

we determine: $ x[n] = cos(\pi*n) = \frac{e^{j*\pi*n} + e^{-j*\pi*n}}{2} $


yields to $ x[t*n] = \frac{te^{j*\pi*n} + t*e^{-j*\pi*n}}{2} $

$ == cos(\pi*n) -> -1 $ on every even integer interval.

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood