(Linearity and Time Invariance)
(Linearity and Time Invariance)
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=Linearity and Time Invariance=
 
=Linearity and Time Invariance=
 
Given system:
 
Given system:
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Input       Output
 
Input       Output
  
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Xk[n]=δ[n-k]   ->  Yk[n]=(k+1)2 δ[n-(k+1)]   ->  For any non-negative integer k
 
Xk[n]=δ[n-k]   ->  Yk[n]=(k+1)2 δ[n-(k+1)]   ->  For any non-negative integer k
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=Time Invariant System?=
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Suppose the system is defined as the third line where input is <math>X_2[n]=&delta;[n-2]</math> and output: <math>Y_2[n]=9 &delta;[n-3]</math> with a time delay of .  Using the same method as in Part D, we can determine whether this system is time invariant or not.
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&delta;[n] -> time delay -> &delta;[n-3] -> system -> 16&delta;[n-4]
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&delta;[n] -> system -> &delta;[n-1] -> time delay -> &delta;[n-4]
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Since both cascades produce different outputs, this system is NON-time invariant.

Revision as of 09:57, 12 September 2008

Linearity and Time Invariance

Given system:

Input Output

X0[n]=δ[n] -> Y0[n]=δ[n-1]

X1[n]=δ[n-1] -> Y1[n]=4δ[n-2]

X2[n]=δ[n-2] -> Y2[n]=9 δ[n-3]

X3[n]=δ[n-3] -> Y3[n]=16 δ[n-4]

... -> ...

Xk[n]=δ[n-k] -> Yk[n]=(k+1)2 δ[n-(k+1)] -> For any non-negative integer k


Time Invariant System?

Suppose the system is defined as the third line where input is $ X_2[n]=&delta;[n-2] $ and output: $ Y_2[n]=9 &delta;[n-3] $ with a time delay of . Using the same method as in Part D, we can determine whether this system is time invariant or not.

δ[n] -> time delay -> δ[n-3] -> system -> 16δ[n-4]

δ[n] -> system -> δ[n-1] -> time delay -> δ[n-4]


Since both cascades produce different outputs, this system is NON-time invariant.

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