(New page: == Original MATLAB code == After running the original program through MATLAB, the following plot was producted:)
 
(Original MATLAB code)
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== Original MATLAB code ==
 
== Original MATLAB code ==
After running the original program through MATLAB, the following plot was producted:
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After running the given MATLAB code, the following plot was produced:
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[[Image:Orig plot_ECE301Fall2008mboutin.png]]
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As seen above, the picture does not resemble a 13Hz sinusoidal wave repeated 13 times.  The function that was suppose to be plotted by the code should be
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<math>\,x(t)=Re[e^{j(2\pi F_{o}t-\frac{pi}{2})}]\,</math>
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<math>\,x(t)=Re[cos(2\pi F_{o}t-\frac{pi}{2})+jsin(2\pi F_{o}t-\frac{pi}{2})]\,</math>
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<math>\,x(t)=cos(2\pi F_{o}t-\frac{pi}{2})\,</math>
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which appears to be correct.  However, the sampling period <math>T_{s}=0.07</math> only provides 14 points on the graph, which appears to be not enough.  If we increase the number of sampling points by a factor of 10 (with a new value <math>T_{s}=0.007</math>), the following plot is produced:
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[[Image:Jkubasci Fixed plot_ECE301Fall2008mboutin.png]]

Revision as of 16:47, 11 September 2008

Original MATLAB code

After running the given MATLAB code, the following plot was produced:

Orig plot ECE301Fall2008mboutin.png

As seen above, the picture does not resemble a 13Hz sinusoidal wave repeated 13 times. The function that was suppose to be plotted by the code should be

$ \,x(t)=Re[e^{j(2\pi F_{o}t-\frac{pi}{2})}]\, $

$ \,x(t)=Re[cos(2\pi F_{o}t-\frac{pi}{2})+jsin(2\pi F_{o}t-\frac{pi}{2})]\, $

$ \,x(t)=cos(2\pi F_{o}t-\frac{pi}{2})\, $

which appears to be correct. However, the sampling period $ T_{s}=0.07 $ only provides 14 points on the graph, which appears to be not enough. If we increase the number of sampling points by a factor of 10 (with a new value $ T_{s}=0.007 $), the following plot is produced:

Jkubasci Fixed plot ECE301Fall2008mboutin.png

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood