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x(t)=sin(t) from 0 to 8*pi | x(t)=sin(t) from 0 to 8*pi | ||
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Revision as of 11:26, 12 September 2008
Periodic Function
I chose the function that Nicholas Browdues has used in the previous Homework 1 assignment as my reference signal. x(t)=sin(t) from 0 to 8*pi