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By sampling the signal with x[n]=tan[k+n] and k=<math>\frac{\pi/8}</math>
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By sampling the signal with x[n]=tan[k+n] and <math>P = {\pi\over 8}</math>

Revision as of 09:32, 11 September 2008

Part A: Periodic Signals Revisited

By sampling a CT periodic signal at different frequencies, one can produce both a periodic and non-periodic DT signal. I chose to use the tangent signal from Homework 1.


$ \tan\theta = \frac{\sin\theta}{\cos\theta}\, $



Tangent ECE301Fall2008mboutin.jpg


By sampling the signal with x[n]=tan[k+n] and k=1.5, it is possible to produce a non-periodic DT signal.

Tan nonperiodic ECE301Fall2008mboutin.jpg


By sampling the signal with x[n]=tan[k+n] and $ P = {\pi\over 8} $

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