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if Y[n] = u[n-1] then k=0 because the function says that | if Y[n] = u[n-1] then k=0 because the function says that | ||
− | <math> | + | <math>delta[n-(k+1)]</math> |
Revision as of 13:00, 10 September 2008
Part A
Can the system be time invariant?
Part B
The system does a phase shift to the right by 1 unit and then multiplies the amplitude of the function by the square of total shift.
if Y[n] = u[n-1] then k=0 because the function says that
$ delta[n-(k+1)] $