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<math>E = \int_{-\infty}^{\infty} \! |e^{j (\pi t)}|^2\ dt</math>
 
<math>E = \int_{-\infty}^{\infty} \! |e^{j (\pi t)}|^2\ dt</math>
  
<math>E = \int_{-\infty}^{\infty} sqrt(\cos^2(\pi t)+\sin^2(\pi t))^2 dt\!</math>
+
<math>E = \int_{-\infty}^{\infty} \sqrt(\cos^2(\pi t)+\sin^2(\pi t))^2 dt\!</math>
  
 
== Signal Power ==
 
== Signal Power ==

Revision as of 05:16, 5 September 2008

Signal Energy

Signal Energy expended from $ t_1\! $ to $ t_2\! $ for CT functions is given by the formula $ E = \int_{t_1}^{t_2} \! |x(t)|^2\ dt $

The total signal energy for a signal can be found by the formula $ E = \int_{-\infty}^{\infty} \! |x(t)|^2\ dt $

For DT signals, the total energy is given by the formula $ E_{\infty} = \sum^{\infty}_{n=-\infty} |x[n]|^2 \! $

Example: $ x(t) = e^{j (\pi t)}\! $

$ E = \int_{-\infty}^{\infty} \! |e^{j (\pi t)}|^2\ dt $

$ E = \int_{-\infty}^{\infty} \sqrt(\cos^2(\pi t)+\sin^2(\pi t))^2 dt\! $

Signal Power

For CT functions, the power of a signal from $ t_1\! $ to $ t_2\! $ is given by the function $ P_{avg}=\frac{1}{t_2-t_1} \int_{t_1}^{t_2} |x(t)|^2\ dt \! $

The total signal power is given by the function $ P_{\infty}=\lim_{t->\infty} \frac{1}{2t} \int_{-t}^{t} |x(t)|^2\ dt \! $

Total signal power for DT signals is given by the formula $ P_{\infty} = \lim_{N->\infty} \frac{1}{2N+1} \sum^{N}_{n=-N} |x[n]|^2\! $

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang