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Say, for example, that you have a sample population of 1000 people, then given that the probability that 0.1% of people are affected by this disease, we can say that 1 person in this thousand are likely to have the disease:
 
Say, for example, that you have a sample population of 1000 people, then given that the probability that 0.1% of people are affected by this disease, we can say that 1 person in this thousand are likely to have the disease:
  
[[File:Bayes Example 4|300px|]]
+
[[File:Bayes_Example_4.PNG|300px|]]
  
 
If everyone in this sample is given a test for the disease, then it is likely that we will have 10 people who test positive for this disease who do not have the disease (false positives, marked in green), and 1 person who tests positive and does have the disease (true positive, marked in red):
 
If everyone in this sample is given a test for the disease, then it is likely that we will have 10 people who test positive for this disease who do not have the disease (false positives, marked in green), and 1 person who tests positive and does have the disease (true positive, marked in red):
  
[[File:Bayes Example 5|300px|]]
+
[[File:Bayes_Example_5.PNG|300px|]]
  
 
Then the person who actually has the disease and tests positive is only 1 among 11 people in the sample who tested positive.
 
Then the person who actually has the disease and tests positive is only 1 among 11 people in the sample who tested positive.
  
[[File:Bayes Example 6|300px|]]
+
[[File:Bayes_Example_6.PNG|300px|]]
  
 
Thus the probability that your test result is a true positive, is 1/11, or roughly 9%
 
Thus the probability that your test result is a true positive, is 1/11, or roughly 9%
  
 
So how does this apply to the real world? For this we will look at data for COVID 19:
 
So how does this apply to the real world? For this we will look at data for COVID 19:

Revision as of 22:25, 27 November 2022

Probability : Group 4

Kalpit Patel Rick Jiang Bowen Wang Kyle Arrowood


Probability, Conditional Probability, Bayes Theorem Disease example

Definition: Probability is a measure of the likelihood of an event to occur. Many events cannot be predicted with total certainty. We can predict only the chance of an event to occur i.e., how likely they are going to happen, using it.


Notation:

1) Sample space (S): Set of all possible outcomes of an experiment (e.g., S={O1,O2,..,On}).

2) Event: Any subsets of outcomes (e.g., A={O1,O2,Ok}) contained in the sample space S.


Formula for probability:

1. Let N:= |S| be the size of sample space

2. Let N(A):= |A| be the number of simple outcomes contained in event A

3. Then P(A) = N(A)/N


Mutually exclusivity:

When events A and B have no outcomes in common Screen Shot 2022-11-15 at 10.56.42.png


Axioms of probability:

1. Probability can range from 0 to 1, where 0 means the event to be an impossible one and 1 indicates a certain event. -> Screen Shot 2022-11-22 at 11.20.02.png

2. The probability of all the events in a sample space adds up to 1. -> P(S) = 1

3. When all events have no outcomes in common. -> Probility.png


Conditional Probability:

Conditional2.png where P(F) > 0

Conditional probability is defined as the likelihood of an event or outcome occurring, based on the occurrence of a previous event or outcome. It is the measure of the probability of an event E, given that another event F has already occurred. Some key points to note here are :


1. P(E|F): Here, E is the event whose probability we are calculating, and F is the event it is conditioned on.

2. "|": Is the symbol used to determine the unknown event (E) and the conditioning event (F).

3. P(F) > 0: The probability of the conditioning event must be positive, otherwise the conditional probability is undefined.

4. In essence, P(E|F) is basically the ratio of the intersection with the conditioning event, so we are measuring how much the conditioning event "influences" the possibility of another event.

Gfg.png



Multiplication Rule:

If we rearrange the terms in our formula, we end up with P(E∩F) = P(E|F)P(F), which means the probability of the intersection of two events E and F can be calculated by the product of the conditional probability of one event given another and the probability of the conditioning event.

But what if we have multiple events which we want to condition? In other words, what if want to find how much the likelihood of a particular event is influenced or altered by the occurrence of more than 1 events, say "N" events namely: E1, E2,....,En.

Multirule.png

This is called the multiplication rule of probability, and is extremely useful in finding the probability of multiple events occurring together.



Independent Events:

This is a special case of Conditional Probability, where the occurrence of one event does not affect the probability of another event. In other words, for two events E and F:

Inde.png




Baye's Theorem Derivation: Starting with the definition of Conditional Probability

Bayes derivation.png

In Step 1 with the definition of conditional probabilities, it is assumed that P(A) and P(B) are not 0.

In Step 2 we multiply both sides by P(B) and in step 3 we multiply both sides by P(A) and we end up with the same result on the right hand side of each.

In Step 4 we are able to set both left sides equal to each other since they both have the same right hand side.

In Step 5 we divide both sides by P(B) and we arrive at Baye's Theorem.

It is also important to introduce the law of total probability:

Total prob.png

The law of total probability is commonly used in Baye's rule. It is very useful, because it provides a way to calculate probabilities by using conditional probabilities. This is used commonly to compute the denominator when given partitions of the conditional probabilities. A quick example using the law of total probability is:

Total prob ex.png

In this example we are able to solve for the probability of A by just using the probability of A given B, the probability of A given the complement of B, and the probability of B.

Baye's Disease Example:

Say for example that you have tested positive for a disease which affects 0.1% of the population using a test which correctly identifies people who have the disease 99% of the time whilst also only incorrectly identifying people who do not have the disease 1% of the time, meaning that it has a false positive rate of 1%, and a true positive rate of 99%. What is the percent chance that you actually have this disease?

Intuitively, you might say that because the test has a success rate of 99%, then the chance that you actually have this disease is also 99%, but you would actually be incorrect.

In order to find that actual probability that you have this disease, we need to use Bayes Theorem on our data. We want to know the probability of having the disease (D), given that we have tested positive (+), thus we want to find P(D|+). We know the probability of someone having the disease is 0.1%, P(D), we also know the probability of testing positive given that you have the disease is 99% P(+|D), and lastly, we know the probability of testing positive given that you don't have the disease is 1% P(+|D'). By plugging these values into the equation for Baye's Rule, we can find the probability of having the disease given we tested positive:

Applying Baye's Rule:

BayesExample1.JPG

By applying the law of total probability, we get:

BayesExample2.JPG

Lastly, by plugging in our values we get:

BayesExample3.JPG

Our final result states that the probability of you actually having the disease if this test returns positive is only about 9%. This result may seem unintuitive, but will make much more sense when viewed from another perspective.

Say, for example, that you have a sample population of 1000 people, then given that the probability that 0.1% of people are affected by this disease, we can say that 1 person in this thousand are likely to have the disease:

File:Bayes Example 4.PNG

If everyone in this sample is given a test for the disease, then it is likely that we will have 10 people who test positive for this disease who do not have the disease (false positives, marked in green), and 1 person who tests positive and does have the disease (true positive, marked in red):

File:Bayes Example 5.PNG

Then the person who actually has the disease and tests positive is only 1 among 11 people in the sample who tested positive.

File:Bayes Example 6.PNG

Thus the probability that your test result is a true positive, is 1/11, or roughly 9%

So how does this apply to the real world? For this we will look at data for COVID 19:

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