Line 40: Line 40:
 
https://www.projectrhea.org/rhea/dropbox_/381ea5db244c12bb92e6de3206725a7a/Wan82_CS5-4.PNG<br>
 
https://www.projectrhea.org/rhea/dropbox_/381ea5db244c12bb92e6de3206725a7a/Wan82_CS5-4.PNG<br>
 
<br>
 
<br>
 +
 
----
 
----
 +
===Similar Problem===
 +
[https://engineering.purdue.edu/ECE/Academics/Graduates/Archived_QE_August_13/CS-5.pdf?dl=1 2013 QE CS5 Prob1]<br>
 +
[https://engineering.purdue.edu/ECE/Academics/Graduates/Archived_QE_August_09/CS-5%20QE%2009.pdf?dl=1 2009 QE CS5 Prob1]<br>
 +
[https://engineering.purdue.edu/ECE/Academics/Graduates/Archived_QE_August_08/CS-5%20QE%2008.pdf?dl=1 2008 QE CS5 Prob3]<br>
 +
 +
----
 +
 
[[QE_2017_CS-5|Back to QE CS question 5, August 2017]]
 
[[QE_2017_CS-5|Back to QE CS question 5, August 2017]]
  
 
[[ECE_PhD_Qualifying_Exams|Back to ECE Qualifying Exams (QE) page]]
 
[[ECE_PhD_Qualifying_Exams|Back to ECE Qualifying Exams (QE) page]]

Latest revision as of 11:00, 25 February 2019


ECE Ph.D. Qualifying Exam

Communication Signal (CS)

Question 5: Image Processing

August 2017 Problem 2


Solution

a)
$ sinc^2(\dfrac{t}{a}) \Rightarrow |a|\Lambda(af) $ (CTFT)
Wan82_CS5-2.PNG

b)
$ y(n)=sinc^2(\dfrac{nT}{a}) \Rightarrow X_s(f)=\dfrac{1}{T}\sum_{k=-\infty}^{\infty} X(f-kF)=\dfrac{|a|}{T}\sum_{k=-\infty}^{\infty}\Lambda(a(f-\dfrac{k}{T})) $

c)
minimum sampling frequency $ \dfrac{1}{T}\ge\dfrac{2}{a} $ $ f\ge\dfrac{2}{a} $ $ T\le\dfrac{a}{2} $

d)
$ T=\dfrac{a}{2} $
Wan82_CS5-3.PNG

e)
$ T=a $
Wan82_CS5-4.PNG


Similar Problem

2013 QE CS5 Prob1
2009 QE CS5 Prob1
2008 QE CS5 Prob3


Back to QE CS question 5, August 2017

Back to ECE Qualifying Exams (QE) page

Alumni Liaison

EISL lab graduate

Mu Qiao