(Non-periodic Functions)
(Periodic Functions)
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A Discrete Time signal is said to be periodic if there exists <math>N > 0</math> (where N is an integer) such that <math>x[n+N]=x[n]</math>
 
A Discrete Time signal is said to be periodic if there exists <math>N > 0</math> (where N is an integer) such that <math>x[n+N]=x[n]</math>
  
An example of a DT periodic signal is <math>x[n] = j^{n}</math> because
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An example of a CT periodic signal is <math>x(t) = sawtooth(t)</math>:
  
<math>x[1] = j</math>         
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[[Image:Example_ECE301Fall2008mboutin.jpg]]
  
<math>x[2] = -1</math>     
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As you can see the function has a fundamental period of two Pi. Therefore any multiple of two Pi is a period.
 
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<math>x[3] = -j</math>
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<math>x[4] = 1</math>   
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<math>x[5] = j</math>   
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<math>x[6] = -1</math>   
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<math>x[7] = -j</math>
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<math>x[8] = 1</math>
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As you can see the function has a fundamental period of 4. Therefore any multiple of 4 is a period.
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== Non-periodic Functions ==
 
== Non-periodic Functions ==

Revision as of 09:37, 5 September 2008

Periodic Functions

A Continuous Time signal is said to be periodic if there exists $ T > 0 $ such that $ x(t+T)=x(t) $

A Discrete Time signal is said to be periodic if there exists $ N > 0 $ (where N is an integer) such that $ x[n+N]=x[n] $

An example of a CT periodic signal is $ x(t) = sawtooth(t) $:

Example ECE301Fall2008mboutin.jpg

As you can see the function has a fundamental period of two Pi. Therefore any multiple of two Pi is a period.

Non-periodic Functions

A Continuous Time signal is said to be non-periodic if there is no value of $ T > 0 $ that satisfies $ x(t+T)=x(t) $

A Discrete Time signal is said to be non-periodic if there is no value of $ N > 0 $ (where N is an integer) that satisfies$ x[n+N]=x[n] $

An example of a non-periodic continuous time signal would be $ \ x(t) = e^{(-1 + j)t} $. This goes to show that not all complex exponential functions are periodic.

Here is what the function looks like when graphed:

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