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Compute the Energy and Power of the signal <math>x(t)=\dfrac{2t}{t^2+5}</math> between 3 and 5 seconds. | Compute the Energy and Power of the signal <math>x(t)=\dfrac{2t}{t^2+5}</math> between 3 and 5 seconds. | ||
==Energy== | ==Energy== | ||
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| + | <math>E=\int_3^{5}{\dfrac{2t}{t^2+5}</}</math> | ||
Revision as of 13:20, 4 September 2008
Compute the Energy and Power of the signal $ x(t)=\dfrac{2t}{t^2+5} $ between 3 and 5 seconds.
Energy
$ E=\int_3^{5}{\dfrac{2t}{t^2+5}</} $
