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If we use a low-pass filter on <math>X_{s}</math>(f), we can obtain the original signal if the repetitions don't overlap.
 
If we use a low-pass filter on <math>X_{s}</math>(f), we can obtain the original signal if the repetitions don't overlap.
  
For this case to be met, <math>1/T_{s} - f_{m}</math> must be greater than <math>f_{m}</math>.
+
For this case to be met, <math>\frac{1}{T_{s}} - f_{m}</math> must be greater than <math>f_{m}</math>.
  
In other words, <math>1/T_{s} > 2f_{m}</math>.
+
In other words,
 +
 
 +
<math>\frac{1}{T_{s}} > 2f_{m}</math>.
  
  

Revision as of 11:29, 4 October 2014


Slecture_Nyquist_Theorem_Stein

The Nyquist Theorem states that it is possible to reproduce a signal from sampled version of that signal given that the sampling frequency is greater than twice the greatest frequency component of the original signal.


Proof

Let's begin by looking at X(f) and $ X_{s} $(f):

MATLAB Plot of X(f)

MATLAB Plot of $ X_{s} $(f)

Observe that $ X_{s} $(f) consists of X(f) repeated every 1/$ T_{s} $.

If we use a low-pass filter on $ X_{s} $(f), we can obtain the original signal if the repetitions don't overlap.

For this case to be met, $ \frac{1}{T_{s}} - f_{m} $ must be greater than $ f_{m} $.

In other words,

$ \frac{1}{T_{s}} > 2f_{m} $.



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BSEE 2004, current Ph.D. student researching signal and image processing.

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