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'''Random Variables and Signals'''
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[[ECE600_F13_notes_mhossain|'''The Comer Lectures on Random Variables and Signals''']]
 
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[https://www.projectrhea.org/learning/slectures.php Slectures] by [[user:Mhossain | Maliha Hossain]]
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<font size= 3> Topic 12: Independent Random Variables</font size>
 
<font size= 3> Topic 12: Independent Random Variables</font size>
 
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We have previously defined statistical independence of two events A and b in ''F''. We will now use that definition to define independence of random variables X and Y.  
 
We have previously defined statistical independence of two events A and b in ''F''. We will now use that definition to define independence of random variables X and Y.  
  

Revision as of 06:59, 26 February 2014

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The Comer Lectures on Random Variables and Signals

Slectures by Maliha Hossain


Topic 12: Independent Random Variables



We have previously defined statistical independence of two events A and b in F. We will now use that definition to define independence of random variables X and Y.

Definition $ \qquad $ Two random variables X and Y on (S,F,P) are statistically independent if the events {X ∈ A}, and {Y ∈ B} are independent ∀A,B ∈ F. i.e.

$ P(\{X\in A\}\cap\{Y\in B\})=P(X\in A)P(Y\in B) \quad\forall A,B\in\mathcal F $

There is an alternative definition of independence for random variables that is often used. We will show that X and Y are independent iff

$ f_{XY}(x,y)=f_X(x)f_Y(y)\quad\forall x,y\in\mathbb R $


First assume that X and Y are independent and let A = (-∞,x], B = (-∞,y]. Then,

$ \begin{align} F_{XY}(x,y) &= P(X\leq x,Y\leq y) \\ &= P(X\in A,Y\in B) \\ &= P(X\in A)P(Y\in B) \\ &= P(X\leq x)P(Y\leq y) \\ &= F_X(x)F_Y(y) \\ \Rightarrow f_{XY}(x,y) &= f_X(x)f_Y(y) \end{align} $

Now assume that f$ _{XY} $(x,y) = f$ _X $(x)f$ _Y $(y) ∀x,y ∈ R. Then, for any A,B ∈ B(R)

$ \begin{align} P(X\in A,Y\in B) &= \int_A\int_Bf_{XY}(x,y)dydx \\ &=\int_A\int_Bf_X(x)f_Y(y)dydx \\ &=\int_Af_X(x)dx\int_Bf_Y(y)dy \\ &= P(X\in A)P(Y\in B) \end{align} $

Thus, X and Y are independent iff f$ _{XY} $(x,y) = f$ _X $(x)f$ _Y $(y).



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