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| + | From Jake Eppehimer: | ||
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| + | Thank you! I will try that when I get home from work. And I am glad I'm not the only one having that exact issue on problem 29... So it's likely a book error? | ||
[[2013_Fall_MA_527_Bell|Back to MA527, Fall 2013]] | [[2013_Fall_MA_527_Bell|Back to MA527, Fall 2013]] | ||
Revision as of 02:56, 28 October 2013
Homework 9 collaboration area
This is the place!
From Jake Eppehimer:
I am not sure how to do number 6 on p. 494. I'm clueless, and there's no answer in the back to verify if I'm doing anything right. Any tips?
From Shawn Whitman: The method of undetermined coefficients for second order nonhomogeneous linear ODEs works well for this problem. See pages 81-84 and use the sum rule. Two of the constants will go to zero. Two others will result in 1/(omega^2-alpha^2) and 1/(omega^2-beta^2); thus the given constraints.
From Mnestero:
I concur with Shawn regarding problem 6. I have a question about the even extension in problem 29. I am getting that the fourier series is 2/pi-4/pi(1/3 cos(2x) + 1/(3*5) cos (4x) + 1/(5*7) *cos(6x)... The answer in the book has odd numbers instead. Their answer doesn't make sense to me. Any thoughts?
From Shawn Whitman: My answer is also different than the one in the back of the book. an is 0 for odd n and -4/pi((n^2)-1) for even n. Note that the (n^2)-1 in the denominator is not a problem for n=1 if you start the summation from 2 instead of 1. This is okay since the odd n’s are zero. ((n^2)-1), for even n, yields 3, 15, 35 or 3*1, 3*5, 5*7 as the book suggests.
From Jayling:
I think the book answer is for Question 28 not 29. If you plot the function it looks like the sawtooth function. Anyway for the Fourier Sine Function did you guys get bn=0 for all n? Which implies that the Fourier Sine Function is equal to zero for all x.
From Jake Eppehimer:
Thank you! I will try that when I get home from work. And I am glad I'm not the only one having that exact issue on problem 29... So it's likely a book error?
